(x+2y)(x-2y)=4；求 |x|+|y| 的最小值。 解不等式 a-(a2-a)≥1 a+(a2-a)≤2 設(shè)A={(x,y)|y2-x-1=0} B={(x,y 若log4（x+2y）+log4（x-2y）=1，則|x|-...
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(x+2y)(x-2y)=4；求 |x|+|y| 的最小值。
x^2-4y^2=4,x^2/4-y^2=1雙曲線，最小值在雙曲線與x軸交點(diǎn)處取得，|x|+|y|=2
解不等式 a-(a2-a)≥1 a+(a2-a)≤2
a^2-2a≤1,a^2≤2
1-√2≤a≤1+√2,-√2≤a≤√2
1-√2≤a≤√2
已知F（x）=log a（x）；g(x)=F(x)[F(x)+2F(2)-1]；
且g(x)在[0.5，2]上單調(diào)遞增；
求a的取值范圍。
g(x)=log a（x）[log a（x）+2log a（2）-1]
|x|+|y| 的最小值是1/2
終爽18013936237： 七年級(jí)數(shù)學(xué)題:已知(x+2y)除以x=4,求(x平方+y平方)除以(x平方—xy—y平方)的值 -
薊縣瓦檢： ______[答案] 已知(x+2y)除以x=4, 1+2y/x=4 y/x=3/2 x/y=2/3 (x平方+y平方)除以(x平方—xy—y平方)的值 =( (x/y)^2+1) /((x/y)^2-x/y-1) =( (2/3)^2+1) /((2/3)^2-2/3-1) =(4/9+1) /(4/9-6/9-1) =(13/9) /(-11/9) =-13/11
終爽18013936237： 求(x加y)(2x減y)減(x加2y)(x減2y)的值,其中x等于3,y等于4求(x+y)(2x - y) - (x+2y)(x - 2y)的值,其中x=3,y=4用平方差的公式計(jì)算 -
薊縣瓦檢： ______[答案] (x+y)(2x-y)-(x+2y)(x-2y) =(x+y)(x+x-y)-x^2+4y^2 =x^2+xy+x^2-y^2-x^2+4y^2 =x^2+xy+3y^2
終爽18013936237： 初一數(shù)學(xué)題 -
薊縣瓦檢： ______ 1、(x^2-1)/(x^2+2x+1)=(x-1)(x+1)/(x+1)^2=(x-1)/(x+1)(2x^2-2))/(4x^2+8x+4)=(x-1)/[2(x+1)]前2個(gè)的結(jié)果:2最后化簡為:2/(x-1)^22、=[(x-y)(x+y)/xy]^2*[1/(x+y)]*(x^...
終爽18013936237： 求二元函數(shù) f(x,y)=x2y2+xy,在條件x+2y=4下的極值這個(gè)是第二題 當(dāng)X>1時(shí),x>1+1nx第一題求二元函數(shù) f(x,y)=x的平方y(tǒng)的平方+xy,在條件x+2y=4下的極值 -
薊縣瓦檢： ______[答案] . 24、二次函數(shù)y=-2x2+4 x-3的圖象的開口向 ;頂點(diǎn)是 . 25、1、將-x4+x2y2因式分解正確的是( ) A、-x2(x2+y2) B、-x2(
終爽18013936237： 方程x^2+xy+y^2=4,為什么兩邊同時(shí)對(duì)X求導(dǎo)得2x+y+xy'+2y*y'=0,xy'和2y*y'中的y'是怎么來的?為什么要這樣做?這有什么規(guī)律么. -
薊縣瓦檢： ______[答案] x^2+xy+y^2=4這個(gè)是隱函數(shù)方程,y是x的函數(shù) 所以兩邊同時(shí)對(duì)X求導(dǎo)時(shí),(y^2)'=2y*y'
終爽18013936237： 已知2x+4y - 4=0求(2^x * 4^y)的平方的值 -
薊縣瓦檢： ______ 2x+4y-4=0<=> x+2y-2=0<=> x+2y=2.[2^x * 4^y]^2=[2^x*2^(2y)]^2=[2^(x+2y)]^2 =4^2=16.
終爽18013936237： x+y=4 xy= - 2,求x - y -
薊縣瓦檢： ______ (x-y)2= (x+y)2-4xy=4*4-4*(-2)=24 x-y=±√24=±2√6
終爽18013936237： 已知x+y=3,xy=1求(x - 2)(y - 2)的值 -
薊縣瓦檢： ______ 原式= xy-2x-2y+4=xy-2(x+y)+4=1+6+4=11
終爽18013936237： 已知x的平方+4y的平方 - 6x+4y+10=0 -
薊縣瓦檢： ______ x的平方+4y的平方-6x+4y+10=0 (x2-6x+9)+(4y2-4y+1)=0(x-3)2+(2y-1)2=0∴x-3=0 2y-1=0∴x=3,y=1/2(x^4-y^4)/(x+2y)2*(x+2y)/xy*y2...
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(x+2y)(x-2y)=4；求 |x|+|y| 的最小值。
x^2-4y^2=4,x^2/4-y^2=1雙曲線，最小值在雙曲線與x軸交點(diǎn)處取得，|x|+|y|=2
解不等式 a-(a2-a)≥1 a+(a2-a)≤2
a^2-2a≤1,a^2≤2
1-√2≤a≤1+√2,-√2≤a≤√2
1-√2≤a≤√2
已知F（x）=log a（x）；g(x)=F(x)[F(x)+2F(2)-1]；
且g(x)在[0.5，2]上單調(diào)遞增；
求a的取值范圍。
g(x)=log a（x）[log a（x）+2log a（2）-1]
|x|+|y| 的最小值是1/2
相關(guān)評(píng)說：
薊縣瓦檢： ______[答案] 已知(x+2y)除以x=4, 1+2y/x=4 y/x=3/2 x/y=2/3 (x平方+y平方)除以(x平方—xy—y平方)的值 =( (x/y)^2+1) /((x/y)^2-x/y-1) =( (2/3)^2+1) /((2/3)^2-2/3-1) =(4/9+1) /(4/9-6/9-1) =(13/9) /(-11/9) =-13/11
薊縣瓦檢： ______[答案] (x+y)(2x-y)-(x+2y)(x-2y) =(x+y)(x+x-y)-x^2+4y^2 =x^2+xy+x^2-y^2-x^2+4y^2 =x^2+xy+3y^2
薊縣瓦檢： ______ 1、(x^2-1)/(x^2+2x+1)=(x-1)(x+1)/(x+1)^2=(x-1)/(x+1)(2x^2-2))/(4x^2+8x+4)=(x-1)/[2(x+1)]前2個(gè)的結(jié)果:2最后化簡為:2/(x-1)^22、=[(x-y)(x+y)/xy]^2*[1/(x+y)]*(x^...
薊縣瓦檢： ______[答案] . 24、二次函數(shù)y=-2x2+4 x-3的圖象的開口向 ;頂點(diǎn)是 . 25、1、將-x4+x2y2因式分解正確的是( ) A、-x2(x2+y2) B、-x2(
薊縣瓦檢： ______[答案] x^2+xy+y^2=4這個(gè)是隱函數(shù)方程,y是x的函數(shù) 所以兩邊同時(shí)對(duì)X求導(dǎo)時(shí),(y^2)'=2y*y'
薊縣瓦檢： ______ 2x+4y-4=0<=> x+2y-2=0<=> x+2y=2.[2^x * 4^y]^2=[2^x*2^(2y)]^2=[2^(x+2y)]^2 =4^2=16.
薊縣瓦檢： ______ (x-y)2= (x+y)2-4xy=4*4-4*(-2)=24 x-y=±√24=±2√6
薊縣瓦檢： ______ 原式= xy-2x-2y+4=xy-2(x+y)+4=1+6+4=11
薊縣瓦檢： ______ x的平方+4y的平方-6x+4y+10=0 (x2-6x+9)+(4y2-4y+1)=0(x-3)2+(2y-1)2=0∴x-3=0 2y-1=0∴x=3,y=1/2(x^4-y^4)/(x+2y)2*(x+2y)/xy*y2...
